When retrieving the last element of a sequence, use
lastOption
rather thanlast
.
Some collections are empty, and last
deals with them by throwing an exception:
Seq.empty[Int].last
// java.util.NoSuchElementException
// at scala.collection.LinearSeqOptimized.last(LinearSeqOptimized.scala:150)
// at scala.collection.LinearSeqOptimized.last$(LinearSeqOptimized.scala:149)
// at scala.collection.immutable.List.last(List.scala:89)
// at repl.Session$App$$anonfun$1.apply$mcI$sp(traversable_last.md:9)
// at repl.Session$App$$anonfun$1.apply(traversable_last.md:9)
// at repl.Session$App$$anonfun$1.apply(traversable_last.md:9)
lastOption
is a safer alternative, since it encodes the possibility of the empty list in its return type:
Seq(1, 2, 3).lastOption
// res0: Option[Int] = Some(3)
Seq.empty[Int].lastOption
// res1: Option[Int] = None
Linter | Rule |
---|---|
Scapegoat |
|
WartRemover |